What is expand (x+1)/((2x-1)(x-1)) ?

The solution to expand (x+1)/((2x-1)(x-1)) is (x+1)/(2x^2-3x+1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (x+1)/((2x-1)(x-1))

expand

\frac{x + 1}{( 2 x - 1 ) ( x - 1 )}

\frac{x + 1}{2 x ^{2} - 3 x + 1}

Solution steps

\frac{x + 1}{( 2 x - 1 ) ( x - 1 )}

Expand

(2 x - 1) (x - 1) : 2 x^{2} - 3 x + 1

= \frac{x + 1}{2 x ^{2} - 3 x + 1}

(x - \frac{1}{9}) (x + \frac{7}{9})

- sin (x) (1 - sin (x))

22 (1 + 9 e^{- 0.1 t})

e^{2 t} u (t - 1)

\frac{( - b + { 2 } ( b ^{2} - 4 a c ) )}{2 a}

What is expand (x+1)/((2x-1)(x-1)) ?
The solution to expand (x+1)/((2x-1)(x-1)) is (x+1)/(2x^2-3x+1)