What is (log_{10}(2)-1)*10 ?

The solution to (log_{10}(2)-1)*10 is 10log_{10}(2)-10

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simplify (log_{10}(2)-1)*10

simplify

(lo g_{10} (2) - 1) \cdot 10

10 lo g_{10} (2) - 10

Solution steps

(lo g_{10} (2) - 1) \cdot 10

= 10 (lo g_{10} (2) - 1)

Apply the distributive law:

a (b - c) = ab - a c

10 (lo g_{10} (2) - 1) = 10 lo g_{10} (2) - 10 \cdot 1

= 10 lo g_{10} (2) - 10 \cdot 1

Multiply the numbers:

10 \cdot 1 = 10

= 10 lo g_{10} (2) - 10

(cos (x) - sin (x))^{2}

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\frac{x}{( 1 - x )}

\frac{5 ( 5 - 2 3 )}{13}

What is (log_{10}(2)-1)*10 ?
The solution to (log_{10}(2)-1)*10 is 10log_{10}(2)-10