What is expand-2(3x^2-8x+4)^2 ?

The solution to expand-2(3x^2-8x+4)^2 is -18x^4+96x^3-176x^2+128x-32

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expand-2(3x^2-8x+4)^2

expand

- 2 (3 x^{2} - 8 x + 4)^{2}

- 18 x^{4} + 96 x^{3} - 176 x^{2} + 128 x - 32

Solution steps

- 2 (3 x^{2} - 8 x + 4)^{2}

(3 x^{2} - 8 x + 4)^{2} = 9 x^{4} - 48 x^{3} + 88 x^{2} - 64 x + 16

= - 2 (9 x^{4} - 48 x^{3} + 88 x^{2} - 64 x + 16)

Distribute parentheses

= (- 2) \cdot 9 x^{4} + (- 2) (- 48 x^{3}) + (- 2) \cdot 88 x^{2} + (- 2) (- 64 x) + (- 2) \cdot 16

Apply minus-plus rules

+ (- a) = - a, (- a) (- b) = ab

= - 2 \cdot 9 x^{4} + 2 \cdot 48 x^{3} - 2 \cdot 88 x^{2} + 2 \cdot 64 x - 2 \cdot 16

Simplify

- 2 \cdot 9 x^{4} + 2 \cdot 48 x^{3} - 2 \cdot 88 x^{2} + 2 \cdot 64 x - 2 \cdot 16 : - 18 x^{4} + 96 x^{3} - 176 x^{2} + 128 x - 32

= - 18 x^{4} + 96 x^{3} - 176 x^{2} + 128 x - 32

e^{x} (1 + e^{- x})

(x^{2} - \frac{3}{x})^{6}

X \cdot Y + λ (\frac{X}{4} + \frac{Y}{9} - 1)

\frac{1}{324} ((2 h - 33 y)^{4} - h^{4})

\frac{2}{5} (x - 0.6065) (x - 0.9512)

What is expand-2(3x^2-8x+4)^2 ?
The solution to expand-2(3x^2-8x+4)^2 is -18x^4+96x^3-176x^2+128x-32