What is expand 48(x/3+y/3)(x/4-y/4) ?

The solution to expand 48(x/3+y/3)(x/4-y/4) is 4x^2-4y^2

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expand 48(x/3+y/3)(x/4-y/4)

expand

48 (\frac{x}{3} + \frac{y}{3}) (\frac{x}{4} - \frac{y}{4})

4 x^{2} - 4 y^{2}

Solution steps

48 (\frac{x}{3} + \frac{y}{3}) (\frac{x}{4} - \frac{y}{4})

Expand

48 (\frac{x}{3} + \frac{y}{3}) (\frac{x}{4} - \frac{y}{4}) : 48 \cdot \frac{x ^{2} - y ^{2}}{12}

= 48 \cdot \frac{x ^{2} - y ^{2}}{12}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{48 ( x ^{2} - y ^{2} )}{12}

Divide the numbers:

\frac{48}{12} = 4

= 4 (x^{2} - y^{2})

Apply the distributive law:

a (b - c) = ab - a c

4 (x^{2} - y^{2}) = 4 x^{2} - 4 y^{2}

= 4 x^{2} - 4 y^{2}

y = x^{3} - 3 x + 2

(x + 2) (x^{2} + 7) (x^{2} - 9)

\frac{1}{x ^{2} ( x ^{2} + a ^{2} )}

(x y + z) (x y - z)

(4 \cdot sin (6 \cdot π \cdot t) + cos (80 \cdot π \cdot t))^{2}

What is expand 48(x/3+y/3)(x/4-y/4) ?
The solution to expand 48(x/3+y/3)(x/4-y/4) is 4x^2-4y^2