What is expand (1+tan(θ))tan(2θ) ?

The solution to expand (1+tan(θ))tan(2θ) is tan(2θ)+tan(2θ)tan(θ)

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expand (1+tan(θ))tan(2θ)

expand

(1 + tan (θ)) tan (2 θ)

tan (2 θ) + tan (2 θ) tan (θ)

Solution steps

(1 + tan (θ)) tan (2 θ)

= tan (2 θ) (1 + tan (θ))

Apply the distributive law:

a (b + c) = ab + a c

tan (2 θ) (1 + tan (θ)) = tan (2 θ) \cdot 1 + tan (2 θ) tan (θ)

= tan (2 θ) \cdot 1 + tan (2 θ) tan (θ)

Apply rule:

a \cdot 1 = a

tan (2 θ) \cdot 1 = tan (2 θ)

= tan (2 θ) + tan (2 θ) tan (θ)

(e^{t} sin (2 t) + cos (2 t) \cdot 2 e^{t})^{2}

a (x + \frac{b}{2 a})^{2} - \frac{b ^{2}}{4 a} + c

\frac{d ^{3}}{d x ^{3}} ((y) (x^{4} - 2 x^{3} + 3 x - 1))

(2 - \frac{1}{4 x})^{5}

1 + \frac{k}{m s ^{2}} (\frac{s + a}{s + b})

What is expand (1+tan(θ))tan(2θ) ?
The solution to expand (1+tan(θ))tan(2θ) is tan(2θ)+tan(2θ)tan(θ)