What is expand ((x-1)/3)((3x+2)/1) ?

The solution to expand ((x-1)/3)((3x+2)/1) is x^2-x/3-2/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand ((x-1)/3)((3x+2)/1)

expand

(\frac{x - 1}{3}) (\frac{3 x + 2}{1})

x^{2} - \frac{x}{3} - \frac{2}{3}

Solution steps

(\frac{x - 1}{3}) (\frac{3 x + 2}{1})

Remove parentheses:

(a) = a

= \frac{x - 1}{3} \cdot \frac{3 x + 2}{1}

Apply rule

\frac{a}{1} = a

= \frac{x - 1}{3} (3 x + 2)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( x - 1 ) ( 3 x + 2 )}{3}

Expand

(x - 1) (3 x + 2) : 3 x^{2} - x - 2

= \frac{3 x ^{2} - x - 2}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{3 x ^{2} - x - 2}{3} = \frac{3 x ^{2}}{3} - \frac{x}{3} - \frac{2}{3}

= \frac{3 x ^{2}}{3} - \frac{x}{3} - \frac{2}{3}

Divide the numbers:

\frac{3}{3} = 1

= x^{2} - \frac{x}{3} - \frac{2}{3}

s t e p (t - 1)

ln ({x (x - 5)})

\frac{1}{( x ^{4} + 1 ) ^{3}}

\frac{1}{e ^{s} ( s ^{2} + 1 )} - \frac{2}{s e ^{2 s} ( s ^{2} + 1 )}

\frac{( x - 1 ) ^{2}}{25}

What is expand ((x-1)/3)((3x+2)/1) ?
The solution to expand ((x-1)/3)((3x+2)/1) is x^2-x/3-2/3