What is expand (log_{10}(2))/(log_{10)(5b)} ?

The solution to expand (log_{10}(2))/(log_{10)(5b)} is log_{5b}(2)

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expand (log_{10}(2))/(log_{10)(5b)}

expand

\frac{lo g _{10} ( 2 )}{lo g _{10} ( 5 b )}

lo g_{5 b} (2)

Solution steps

\frac{lo g _{10} ( 2 )}{lo g _{10} ( 5 b )}

Apply log rule:

\frac{lo g _{c} ( b )}{lo g _{c} ( a )} = lo g_{a} (b)

\frac{lo g _{10} ( 2 )}{lo g _{10} ( 5 b )} = lo g_{5 b} (2)

= lo g_{5 b} (2)

4 (x^{2} + y^{2}) (2 x + 2 y \frac{d y}{d x})

\frac{1}{( s - 2 ) ( s + 1 )}

\frac{2 X + 1}{( X - 1 ) ( 2 X ^{3} + 6 X ^{2} - X + 4 )}

e^{- i \cdot x} \cdot (6 + e^{i \cdot x} + e^{- i \cdot x})

d (cos (x) + 2)

What is expand (log_{10}(2))/(log_{10)(5b)} ?
The solution to expand (log_{10}(2))/(log_{10)(5b)} is log_{5b}(2)