What is expand (3^{n+2}-(-1)^n)/4 ?

The solution to expand (3^{n+2}-(-1)^n)/4 is (3^{n+2})/4-((-1)^n)/4

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expand (3^{n+2}-(-1)^n)/4

expand

\frac{3 ^{n + 2} - ( - 1 ) ^{n}}{4}

\frac{3 ^{n + 2}}{4} - \frac{( - 1 ) ^{n}}{4}

Solution steps

\frac{3 ^{n + 2} - ( - 1 ) ^{n}}{4}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{3 ^{n + 2} - ( - 1 ) ^{n}}{4} = \frac{3 ^{n + 2}}{4} - \frac{( - 1 ) ^{n}}{4}

= \frac{3 ^{n + 2}}{4} - \frac{( - 1 ) ^{n}}{4}

cos (t) h (t - π)

3 - 3 [3 - \frac{( 2 + ( - 5 ) )}{( 3 - 6 )}] - 2 [2 - (- 6)]

- \frac{50 x ^{4}}{( x ^{5} + 5 ) ( x ^{5} - 5 )}

(3, 4) y (- 2, - 3)

\frac{1 - 3 x ^{2}}{x ( 1 - x ^{2} )}

What is expand (3^{n+2}-(-1)^n)/4 ?
The solution to expand (3^{n+2}-(-1)^n)/4 is (3^{n+2})/4-((-1)^n)/4