What is expand log_{4}(4)(x-3) ?

The solution to expand log_{4}(4)(x-3) is x-3

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expand log_{4}(4)(x-3)

expand

lo g_{4} (4) (x - 3)

x - 3

Solution steps

lo g_{4} (4) (x - 3)

Apply the distributive law:

a (b - c) = ab - a c

lo g_{4} (4) (x - 3) = lo g_{4} (4) x - lo g_{4} (4) \cdot 3

= lo g_{4} (4) x - lo g_{4} (4) \cdot 3

Simplify

lo g_{4} (4) x - lo g_{4} (4) \cdot 3 : x - 3

= x - 3

11 (8 r + 3) - 2 (- 9 = 6 r)

\frac{( x - 1 ) ^{2}}{4 x}

\frac{3 ( x + h ) - 2 - 3 x - 2}{h}

(y 6 - 3) (y 6 + 3)

\frac{4 ( 3 s + 1 )}{( 3 s + 2 ) ( s + 1 ) ( 5 s + 7 )}