What is expand (4/((n+1)(n+2)))^{1/n} ?

The solution to expand (4/((n+1)(n+2)))^{1/n} is (4/(n^2+3n+2))^{1/n}

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expand (4/((n+1)(n+2)))^{1/n}

expand

(\frac{4}{( n + 1 ) ( n + 2 )})^{\frac{1}{n}}

(\frac{4}{n ^{2} + 3 n + 2})^{\frac{1}{n}}

Solution steps

(\frac{4}{( n + 1 ) ( n + 2 )})^{\frac{1}{n}}

\frac{4}{( n + 1 ) ( n + 2 )} = \frac{4}{n ^{2} + 3 n + 2}

= (\frac{4}{n ^{2} + 3 n + 2})^{\frac{1}{n}}

\frac{i w + a}{( i w + a ) ^{2} + b ^{2}}

2 (\frac{3}{2} x - \frac{1}{2} y)^{2}

\frac{7}{s ( s + 3 ) ( s + 2 )}

\frac{x ^{2} - 4 x + 3}{( x + 1 ) ^{2}}

\frac{1}{s ( s + a ) ^{2}}

What is expand (4/((n+1)(n+2)))^{1/n} ?
The solution to expand (4/((n+1)(n+2)))^{1/n} is (4/(n^2+3n+2))^{1/n}