What is expand (ucos^2(v)+usin^2(v))^2 ?

The solution to expand (ucos^2(v)+usin^2(v))^2 is u^2cos^4(v)+2u^2cos^2(v)sin^2(v)+u^2sin^4(v)

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expand (ucos^2(v)+usin^2(v))^2

expand

(u cos^{2} (v) + u sin^{2} (v))^{2}

u^{2} cos^{4} (v) + 2 u^{2} cos^{2} (v) sin^{2} (v) + u^{2} sin^{4} (v)

Solution steps

(u cos^{2} (v) + u sin^{2} (v))^{2}

Apply Perfect Square Formula:

(a + b)^{2} = a^{2} + 2 ab + b^{2}

(u cos^{2} (v) + u sin^{2} (v))^{2} = (u cos^{2} (v))^{2} + 2 u cos^{2} (v) u sin^{2} (v) + (u sin^{2} (v))^{2}

= (u cos^{2} (v))^{2} + 2 u cos^{2} (v) u sin^{2} (v) + (u sin^{2} (v))^{2}

Simplify

(u cos^{2} (v))^{2} + 2 u cos^{2} (v) u sin^{2} (v) + (u sin^{2} (v))^{2} : u^{2} cos^{4} (v) + 2 u^{2} cos^{2} (v) sin^{2} (v) + u^{2} sin^{4} (v)

= u^{2} cos^{4} (v) + 2 u^{2} cos^{2} (v) sin^{2} (v) + u^{2} sin^{4} (v)

(27, - 53) y (- 35, - 45)

(3 + cos (θ))^{3} 0.3

\frac{( x + 3 ) ( x - 8 )}{x}

\frac{1}{2} (arcsin (x) - \frac{1}{2} sin (2 arcsin (x))) + C

(x^{\frac{1}{4}} + y^{\frac{1}{4}}) (x^{\frac{1}{4}} - y^{\frac{1}{4}})

What is expand (ucos^2(v)+usin^2(v))^2 ?
The solution to expand (ucos^2(v)+usin^2(v))^2 is u^2cos^4(v)+2u^2cos^2(v)sin^2(v)+u^2sin^4(v)