What is expand 3/2 sin(2x)(3cos(2x)-1) ?

The solution to expand 3/2 sin(2x)(3cos(2x)-1) is (9sin(4x))/4-(3sin(2x))/2

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expand 3/2 sin(2x)(3cos(2x)-1)

expand

\frac{3}{2} sin (2 x) (3 cos (2 x) - 1)

\frac{9 sin ( 4 x )}{4} - \frac{3 sin ( 2 x )}{2}

Solution steps

\frac{3}{2} sin (2 x) (3 cos (2 x) - 1)

Apply the distributive law:

a (b - c) = ab - a c

\frac{3}{2} sin (2 x) (3 cos (2 x) - 1) = \frac{3}{2} sin (2 x) \cdot 3 cos (2 x) - \frac{3}{2} sin (2 x) \cdot 1

= \frac{3}{2} sin (2 x) \cdot 3 cos (2 x) - \frac{3}{2} sin (2 x) \cdot 1

Simplify

\frac{3}{2} sin (2 x) \cdot 3 cos (2 x) - \frac{3}{2} sin (2 x) \cdot 1 : \frac{9 sin ( 4 x )}{4} - \frac{3 sin ( 2 x )}{2}

= \frac{9 sin ( 4 x )}{4} - \frac{3 sin ( 2 x )}{2}

\frac{d}{d x} ((x + 6) \cdot e^{3 x}) + 4

(y - \frac{7}{4})^{2}

(4 x^{2} + x) e^{2 x + 2}

\frac{1}{( s ( s ^{2} + 1 ) )}

What is expand 3/2 sin(2x)(3cos(2x)-1) ?
The solution to expand 3/2 sin(2x)(3cos(2x)-1) is (9sin(4x))/4-(3sin(2x))/2