What is expand ((x-5)^3)/3 ?

The solution to expand ((x-5)^3)/3 is (x^3)/3-5x^2+25x-125/3

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expand ((x-5)^3)/3

expand

\frac{( x - 5 ) ^{3}}{3}

\frac{x ^{3}}{3} - 5 x^{2} + 25 x - \frac{125}{3}

Solution steps

\frac{( x - 5 ) ^{3}}{3}

(x - 5)^{3} = x^{3} - 15 x^{2} + 75 x - 125

= \frac{x ^{3} - 15 x ^{2} + 75 x - 125}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{3} - 15 x ^{2} + 75 x - 125}{3} = \frac{x ^{3}}{3} - \frac{15 x ^{2}}{3} + \frac{75 x}{3} - \frac{125}{3}

= \frac{x ^{3}}{3} - \frac{15 x ^{2}}{3} + \frac{75 x}{3} - \frac{125}{3}

Divide the numbers:

\frac{15}{3} = 5

= \frac{x ^{3}}{3} - 5 x^{2} + \frac{75 x}{3} - \frac{125}{3}

Divide the numbers:

\frac{75}{3} = 25

= \frac{x ^{3}}{3} - 5 x^{2} + 25 x - \frac{125}{3}

\frac{n ( 3 n - 1 )}{2}

\frac{x ^{2} + 5 x + 7}{( x ^{2} + 4 x + 5 ) ( s + 1 ) ^{2}}

, (8 x^{2} - 8) + (- 2 x^{2} - 9 x)

\frac{( sin ^{2} ( t ) )}{( 1 - cos ( t ) ) ^{2}}

(e^{- t} + 1)^{2}

What is expand ((x-5)^3)/3 ?
The solution to expand ((x-5)^3)/3 is (x^3)/3-5x^2+25x-125/3