What is expand (e^{2pi}-1)(e^{2pi}+1) ?

The solution to expand (e^{2pi}-1)(e^{2pi}+1) is e^{4pi}-1

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expand (e^{2pi}-1)(e^{2pi}+1)

expand

(e^{2 π} - 1) (e^{2 π} + 1)

e^{4 π} - 1

Solution steps

(e^{2 π} - 1) (e^{2 π} + 1)

Apply Difference of Two Squares Formula:

(a - b) (a + b) = a^{2} - b^{2}

a = e^{2 π}, b = 1

= (e^{2 π})^{2} - 1^{2}

Simplify

(e^{2 π})^{2} - 1^{2} : e^{4 π} - 1

= e^{4 π} - 1

A (1, - 1) B (- 7, 3)

\frac{10 - ( x - 4 ) x ( x ^{2} - 3 x - 2 )}{( x - 4 ) x}

x (\frac{x ^{4} - 5 x ^{2}}{2} + \frac{15}{4})

12 (m - \frac{1}{2})

(4 x - 8 y) (4 x + 8 y)

What is expand (e^{2pi}-1)(e^{2pi}+1) ?
The solution to expand (e^{2pi}-1)(e^{2pi}+1) is e^{4pi}-1