What is expand ((s^3-3s))/((s^4-9)) ?

The solution to expand ((s^3-3s))/((s^4-9)) is s/(s^2+3)

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expand ((s^3-3s))/((s^4-9))

expand

\frac{( s ^{3} - 3 s )}{( s ^{4} - 9 )}

\frac{s}{s ^{2} + 3}

Solution steps

\frac{s ^{3} - 3 s}{s ^{4} - 9}

Factor

s^{3} - 3 s : s (s + 3) (s - 3)

= \frac{s ( s + 3 ) ( s - 3 )}{s ^{4} - 9}

Factor

s^{4} - 9 : (s^{2} + 3) (s + 3) (s - 3)

= \frac{s ( s + 3 ) ( s - 3 )}{( s ^{2} + 3 ) ( s + 3 ) ( s - 3 )}

Cancel

\frac{s ( s + 3 ) ( s - 3 )}{( s ^{2} + 3 ) ( s + 3 ) ( s - 3 )} : \frac{s}{s ^{2} + 3}

= \frac{s}{s ^{2} + 3}

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\frac{\partial}{\partial x} ((z) (x^{4} y + x z + y z^{2}))

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What is expand ((s^3-3s))/((s^4-9)) ?
The solution to expand ((s^3-3s))/((s^4-9)) is s/(s^2+3)