What is expand (6x^2+7x+9)/(3x) ?

The solution to expand (6x^2+7x+9)/(3x) is 2x+7/3+3/x

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expand (6x^2+7x+9)/(3x)

expand

\frac{6 x ^{2} + 7 x + 9}{3 x}

2 x + \frac{7}{3} + \frac{3}{x}

Solution steps

\frac{6 x ^{2} + 7 x + 9}{3 x}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{6 x ^{2} + 7 x + 9}{3 x} = \frac{6 x ^{2}}{3 x} + \frac{7 x}{3 x} + \frac{9}{3 x}

= \frac{6 x ^{2}}{3 x} + \frac{7 x}{3 x} + \frac{9}{3 x}

Cancel

\frac{6 x ^{2}}{3 x} : 2 x

= 2 x + \frac{7 x}{3 x} + \frac{9}{3 x}

Cancel

\frac{7 x}{3 x} : \frac{7}{3}

= 2 x + \frac{7}{3} + \frac{9}{3 x}

Divide the numbers:

\frac{9}{3} = 3

= 2 x + \frac{7}{3} + \frac{3}{x}

\frac{( a - x ) ^{4}}{4}

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\frac{s ^{2} + 4 s + 2}{s ( s + 2 ) ( s + 4 )}

(2 \times (- 5) γ)^{3}

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What is expand (6x^2+7x+9)/(3x) ?
The solution to expand (6x^2+7x+9)/(3x) is 2x+7/3+3/x