What is (s/2+1)(s/8+1) ?

The solution to (s/2+1)(s/8+1) is ((2+s)(8+s))/(16)

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simplify (s/2+1)(s/8+1)

simplify

(\frac{s}{2} + 1) (\frac{s}{8} + 1)

\frac{( 2 + s ) ( 8 + s )}{16}

Solution steps

(\frac{s}{2} + 1) (\frac{s}{8} + 1)

Join

\frac{s}{2} + 1 : \frac{2 + s}{2}

= \frac{2 + s}{2} (\frac{s}{8} + 1)

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 2 + s ) ( \frac{s}{8} + 1 )}{2}

Simplify

(2 + s) (\frac{s}{8} + 1) : \frac{( 2 + s ) ( 8 + s )}{8}

= \frac{\frac{( 2 + s ) ( 8 + s )}{8}}{2}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{( 2 + s ) ( 8 + s )}{8 \cdot 2}

Multiply the numbers:

8 \cdot 2 = 16

= \frac{( 2 + s ) ( 8 + s )}{16}

\frac{( x ^{2} + 4 x + 2 )}{( ( x + 2 ) ( x - 1 ) )}

\frac{e ^{- 2 (s + 1)}}{s + 1} + \frac{3 e ^{- 2 s}}{s}

2 + 3

(y - 3)^{2}

(x - \frac{4}{3}) (x + \frac{4}{3})