What is (1+1/(8n))x^2-2x+1 ?

The solution to (1+1/(8n))x^2-2x+1 is ((8n+1)x^2)/(8n)-2x+1

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simplify (1+1/(8n))x^2-2x+1

simplify

(1 + \frac{1}{8 n}) x^{2} - 2 x + 1

\frac{( 8 n + 1 ) x ^{2}}{8 n} - 2 x + 1

Solution steps

(1 + \frac{1}{8 n}) x^{2} - 2 x + 1

Join

1 + \frac{1}{8 n} : \frac{8 n + 1}{8 n}

= \frac{8 n + 1}{8 n} x^{2} - 2 x + 1

Simplify

\frac{8 n + 1}{8 n} x^{2} : \frac{( 8 n + 1 ) x ^{2}}{8 n}

= \frac{( 8 n + 1 ) x ^{2}}{8 n} - 2 x + 1

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\frac{3 ( x + h ) + 1 - 3 x + 1}{h}

\frac{d x}{( 5 x + 2 ) ^{2}}

L^{2 (b + 6)} - U^{2} p^{2}

\frac{1}{( x + 4 ) ( x - a )}

What is (1+1/(8n))x^2-2x+1 ?
The solution to (1+1/(8n))x^2-2x+1 is ((8n+1)x^2)/(8n)-2x+1