What is expand (1+2x)/((3x-1)^2) ?

The solution to expand (1+2x)/((3x-1)^2) is (1+2x)/(9x^2-6x+1)

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expand (1+2x)/((3x-1)^2)

expand

\frac{1 + 2 x}{( 3 x - 1 ) ^{2}}

\frac{1 + 2 x}{9 x ^{2} - 6 x + 1}

Solution steps

\frac{1 + 2 x}{( 3 x - 1 ) ^{2}}

(3 x - 1)^{2} = 9 x^{2} - 6 x + 1

= \frac{1 + 2 x}{9 x ^{2} - 6 x + 1}

(y - x)^{2} d x

\frac{( s + 2 )}{( s \cdot ( s + 3 ) \cdot ( s + 1 ) )}

\frac{t - x - 1}{( t - x ) ^{2} ( t + x )}

(2 t + 3 t^{2}) \cdot (4 e^{t^{2} - 1} + 10 t^{4})

49 π (19 e^{20} + 1)

What is expand (1+2x)/((3x-1)^2) ?
The solution to expand (1+2x)/((3x-1)^2) is (1+2x)/(9x^2-6x+1)