What is expand 1/((s+1)(s^3+3s^2+3s+1)) ?

The solution to expand 1/((s+1)(s^3+3s^2+3s+1)) is 1/(s^4+4s^3+6s^2+4s+1)

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expand 1/((s+1)(s^3+3s^2+3s+1))

expand

\frac{1}{( s + 1 ) ( s ^{3} + 3 s ^{2} + 3 s + 1 )}

\frac{1}{s ^{4} + 4 s ^{3} + 6 s ^{2} + 4 s + 1}

Solution steps

\frac{1}{( s + 1 ) ( s ^{3} + 3 s ^{2} + 3 s + 1 )}

Expand

(s + 1) (s^{3} + 3 s^{2} + 3 s + 1) : s^{4} + 4 s^{3} + 6 s^{2} + 4 s + 1

= \frac{1}{s ^{4} + 4 s ^{3} + 6 s ^{2} + 4 s + 1}

e^{x} (1 - 3 e^{- 2 x})

\frac{4 ( 1 - 9 x ^{2} )}{( 1 + 3 x ^{2} ) ^{3}}

cos^{2} (x) (1 - cos^{4} (x))

\frac{1 + 4 x}{4 ( x + 1 )}

\frac{s + 1}{( s ^{2} + 1 ) ^{3}}

What is expand 1/((s+1)(s^3+3s^2+3s+1)) ?
The solution to expand 1/((s+1)(s^3+3s^2+3s+1)) is 1/(s^4+4s^3+6s^2+4s+1)