What is expand-(x+1)*e^{x+2} ?

The solution to expand-(x+1)*e^{x+2} is -e^{x+2}x-e^{x+2}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand-(x+1)*e^{x+2}

expand

- (x + 1) \cdot e^{x + 2}

- e^{x + 2} x - e^{x + 2}

Solution steps

- (x + 1) e^{x + 2}

= - e^{x + 2} (x + 1)

Apply the distributive law:

a (b + c) = ab + a c

a = - e^{x + 2}, b = x, c = 1

= - e^{x + 2} x + (- e^{x + 2}) \cdot 1

Apply minus-plus rules

+ (- a) = - a

= - e^{x + 2} x - 1 \cdot e^{x + 2}

Multiply:

1 \cdot e^{x + 2} = e^{x + 2}

= - e^{x + 2} x - e^{x + 2}

4 c i s (\frac{161 π}{180}) \cdot e^{\frac{1}{5} πi}

\frac{1}{9} (e^{3 x} \cdot 3 x - e^{3 x}) (e^{x})

2 (5 + 3)

2 (37 + 83)

\frac{d ^{2}}{d x ^{2}} ((y) (4 x^{7} - 5 x^{2} + x))

What is expand-(x+1)*e^{x+2} ?
The solution to expand-(x+1)*e^{x+2} is -e^{x+2}x-e^{x+2}