What is expand ((x-2)(x-3))/(x+2) ?

The solution to expand ((x-2)(x-3))/(x+2) is (x^2-5x+6)/(x+2)

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expand ((x-2)(x-3))/(x+2)

expand

\frac{( x - 2 ) ( x - 3 )}{x + 2}

\frac{x ^{2} - 5 x + 6}{x + 2}

Solution steps

\frac{( x - 2 ) ( x - 3 )}{x + 2}

Expand

(x - 2) (x - 3) : x^{2} - 5 x + 6

= \frac{x ^{2} - 5 x + 6}{x + 2}

\frac{1}{k ( k + 1 )} + (k + 1)

(2 - 4 i)^{7}

(x + 1) ln (3)

(Δ x + x)^{2}

\frac{3 x + 4}{( 6 x ^{2} + 16 x ) ^{3}}

What is expand ((x-2)(x-3))/(x+2) ?
The solution to expand ((x-2)(x-3))/(x+2) is (x^2-5x+6)/(x+2)