What is expand 1/(s^2(s^2+6s+9)) ?

The solution to expand 1/(s^2(s^2+6s+9)) is 1/(s^4+6s^3+9s^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand 1/(s^2(s^2+6s+9))

expand

\frac{1}{s ^{2} ( s ^{2} + 6 s + 9 )}

\frac{1}{s ^{4} + 6 s ^{3} + 9 s ^{2}}

Solution steps

\frac{1}{s ^{2} ( s ^{2} + 6 s + 9 )}

Expand

s^{2} (s^{2} + 6 s + 9) : s^{4} + 6 s^{3} + 9 s^{2}

= \frac{1}{s ^{4} + 6 s ^{3} + 9 s ^{2}}

\frac{( ( c + h ) sin ( \frac{1}{c + h} ) - ( c ) sin ( \frac{1}{c} ) )}{h}

(1 - u) (u)^{\frac{1}{2}}

2 x (x d t + 2 t d x)

sin (u) (3 - 4 sin^{3} (u))

(2 x + 5) l e f t (3 x - 4)

What is expand 1/(s^2(s^2+6s+9)) ?
The solution to expand 1/(s^2(s^2+6s+9)) is 1/(s^4+6s^3+9s^2)