What is expand ((-x+3)^3)/3 ?

The solution to expand ((-x+3)^3)/3 is -(x^3)/3+3x^2-9x+9

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expand ((-x+3)^3)/3

expand

\frac{( - x + 3 ) ^{3}}{3}

- \frac{x ^{3}}{3} + 3 x^{2} - 9 x + 9

Solution steps

\frac{( - x + 3 ) ^{3}}{3}

(- x + 3)^{3} = - x^{3} + 9 x^{2} - 27 x + 27

= \frac{( - x ^{3} + 9 x ^{2} - 27 x + 27 )}{3}

Remove parentheses:

(- a) = - a

= \frac{- x ^{3} + 9 x ^{2} - 27 x + 27}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{- x ^{3} + 9 x ^{2} - 27 x + 27}{3} = - \frac{x ^{3}}{3} + \frac{9 x ^{2}}{3} - \frac{27 x}{3} + \frac{27}{3}

= - \frac{x ^{3}}{3} + \frac{9 x ^{2}}{3} - \frac{27 x}{3} + \frac{27}{3}

Divide the numbers:

\frac{9}{3} = 3

= - \frac{x ^{3}}{3} + 3 x^{2} - \frac{27 x}{3} + \frac{27}{3}

Divide the numbers:

\frac{27}{3} = 9

= - \frac{x ^{3}}{3} + 3 x^{2} - 9 x + 9

cosh ((x - b) (x - c))

(1 - z^{- 1}) (1 - z^{- 1})^{2}

\frac{( 3 x ^{2} + 7 ) ^{6}}{( 5 x ^{3} + 1 ) ^{4}}

(4 - x^{2}) d x

\frac{1}{( x ^{2} + 6 x + 5 ) ^{2}}

What is expand ((-x+3)^3)/3 ?
The solution to expand ((-x+3)^3)/3 is -(x^3)/3+3x^2-9x+9