What is expand-1/2 \H(t-2pi)sinh(2(t-2pi)) ?

The solution to expand-1/2 \H(t-2pi)sinh(2(t-2pi)) is -1/2 \H(t-2pi)sinh(2t-4pi)

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expand-1/2 \H(t-2pi)sinh(2(t-2pi))

expand

- \frac{1}{2} H (t - 2 π) sinh (2 (t - 2 π))

- \frac{1}{2} H (t - 2 π) sinh (2 t - 4 π)

Solution steps

- \frac{1}{2} H (t - 2 π) sinh (2 (t - 2 π))

Expand

2 (t - 2 π) : 2 t - 4 π

= - \frac{1}{2} H (t - 2 π) sinh (2 t - 4 π)

sin (x) (\frac{sin ^{3} ( x )}{3} - sin (x))

(1 + e^{x}) (1 - e^{x})

25 (1 + cos (θ))

A (4, 1) y B (- 2, - 2)

(t^{2} + 1) y^{'} (t) + t y - 2 t

What is expand-1/2 \H(t-2pi)sinh(2(t-2pi)) ?
The solution to expand-1/2 \H(t-2pi)sinh(2(t-2pi)) is -1/2 \H(t-2pi)sinh(2t-4pi)