What is expand (e^x)(xe^x+e^x) ?

The solution to expand (e^x)(xe^x+e^x) is e^{2x}x+e^{2x}

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expand (e^x)(xe^x+e^x)

expand

(e^{x}) (x e^{x} + e^{x})

e^{2 x} x + e^{2 x}

Solution steps

(e^{x}) (x e^{x} + e^{x})

= (e^{x}) (e^{x} x + e^{x})

Apply the distributive law:

a (b + c) = ab + a c

a = (e^{x}), b = x e^{x}, c = e^{x}

= (e^{x}) x e^{x} + (e^{x}) e^{x}

= e^{x} x (e^{x}) + e^{x} (e^{x})

Simplify

e^{x} x (e^{x}) + e^{x} (e^{x}) : e^{2 x} x + e^{2 x}

= e^{2 x} x + e^{2 x}

\frac{( 3 x a + b ) ^{3}}{27 a ^{3}}

\frac{( 1 - cos ( 8 x ) ) ^{2}}{4}

\frac{2}{( s ^{2} + 2 ) ( s ^{2} + 1 )} + \frac{1}{( s ^{2} + 1 )}

\frac{- 1 - x}{( x - 1 ) ^{3}}

What is expand (e^x)(xe^x+e^x) ?
The solution to expand (e^x)(xe^x+e^x) is e^{2x}x+e^{2x}