What is expand ((x'-3sqrt(2))^2)/(16) ?

The solution to expand ((x'-3sqrt(2))^2)/(16) is ((x')^2)/(16)-(3x')/(4sqrt(2))+9/8

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expand ((x'-3sqrt(2))^2)/(16)

expand

\frac{( x ^{'} - 3 2 ) ^{2}}{16}

\frac{( x ' ) ^{2}}{16} - \frac{3 x '}{4 2} + \frac{9}{8}

Solution steps

\frac{( x ^{'} - 3 2 ) ^{2}}{16}

(x^{'} - 32)^{2} = (x^{'})^{2} - 62 x^{'} + 18

= \frac{( x ^{^{'}} ) ^{2} - 6 2 x ^{^{'}} + 18}{16}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{( x ^{'} ) ^{2} - 6 2 x ^{'} + 18}{16} = \frac{( x ^{'} ) ^{2}}{16} - \frac{6 2 x ^{'}}{16} + \frac{18}{16}

= \frac{( x ^{^{'}} ) ^{2}}{16} - \frac{6 2 x ^{^{'}}}{16} + \frac{18}{16}

\frac{6 2 x ^{'}}{16} = \frac{3 x ^{'}}{4 2}

\frac{18}{16} = \frac{9}{8}

= \frac{( x ^{^{'}} ) ^{2}}{16} - \frac{3 x ^{^{'}}}{4 2} + \frac{9}{8}

(csc (x) + 1) l e f t (csc (x) - 1) a n^{2} x

(1 + 9 - x^{2}) d x

2 (2 x + 3 = 21)

\frac{( 7 a - 14 )}{2 ( a - 2 b )}

x^{2} (2 - x) + \frac{1}{3} (2 - x)^{3} + (2 - x)

What is expand ((x'-3sqrt(2))^2)/(16) ?
The solution to expand ((x'-3sqrt(2))^2)/(16) is ((x')^2)/(16)-(3x')/(4sqrt(2))+9/8