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Popular >

5k<= k(k-2)

Solution

5 k \leq k (k - 2)

Solution

k \leq 0 or k \geq 7

+1

Interval Notation

(- \infty, 0] \cup [7, \infty)

Solution steps

5 k \leq k (k - 2)

Rewrite in standard form

7 k - k^{2} \leq 0

Factor

7 k - k^{2} : - k (k - 7)

- k (k - 7) \leq 0

Multiply both sides by

- 1

(reverse the inequality)

(- k (k - 7)) (- 1) \geq 0 \cdot (- 1)

Simplify

k (k - 7) \geq 0

Identify the intervals

k \leq 0 or k \geq 7

Popular Examples

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15 n^{2} - n - 2

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4 x = 12

(2 u) (u + 4) = 0

simplify-14x^2y(-3x^2)simplify

- 14 x^{2} y (- 3 x^{2})

Frequently Asked Questions (FAQ)

What is 5k<= k(k-2) ?
The solution to 5k<= k(k-2) is k<= 0\lor k>= 7