What is expand ((2+x)^2)/3-17/4 x ?

The solution to expand ((2+x)^2)/3-17/4 x is (x^2)/3-(35x)/(12)+4/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand ((2+x)^2)/3-17/4 x

expand

\frac{( 2 + x ) ^{2}}{3} - \frac{17}{4} x

\frac{x ^{2}}{3} - \frac{35 x}{12} + \frac{4}{3}

Solution steps

\frac{( 2 + x ) ^{2}}{3} - \frac{17}{4} x

(2 + x)^{2} = 4 + 4 x + x^{2}

= \frac{x ^{2} + 4 x + 4}{3} - \frac{17}{4} x

Multiply

\frac{17}{4} x : \frac{17 x}{4}

= \frac{x ^{2} + 4 x + 4}{3} - \frac{17 x}{4}

Least Common Multiplier of

3, 4 : 12

Adjust Fractions based on the LCM

= \frac{( 4 + 4 x + x ^{2} ) \cdot 4}{12} - \frac{51 x}{12}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{( 4 + 4 x + x ^{2} ) \cdot 4 - 51 x}{12}

Expand

(4 + 4 x + x^{2}) \cdot 4 - 51 x : 4 x^{2} - 35 x + 16

= \frac{4 x ^{2} - 35 x + 16}{12}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{4 x ^{2} - 35 x + 16}{12} = \frac{4 x ^{2}}{12} - \frac{35 x}{12} + \frac{16}{12}

= \frac{4 x ^{2}}{12} - \frac{35 x}{12} + \frac{16}{12}

Cancel

\frac{4 x ^{2}}{12} : \frac{x ^{2}}{3}

= \frac{x ^{2}}{3} - \frac{35 x}{12} + \frac{16}{12}

Cancel

\frac{16}{12} : \frac{4}{3}

= \frac{x ^{2}}{3} - \frac{35 x}{12} + \frac{4}{3}

(- 139, 46 - 160, 43 i) - (- 61.87 + 219, 39 i)

\frac{( ( 1 - cos ( x ) ) ^{2} + sin ^{2} ( x ) )}{1 - cos ( x )}

\frac{13}{n ( n + 1 )}

\frac{3 x + 4}{( x + 4 ) ( x ^{2} + x - 4 ) ^{2}}

What is expand ((2+x)^2)/3-17/4 x ?
The solution to expand ((2+x)^2)/3-17/4 x is (x^2)/3-(35x)/(12)+4/3