What is expand-1/4 sin^3(x)cos(x)+3/8 (x-sin(2x)) ?

The solution to expand-1/4 sin^3(x)cos(x)+3/8 (x-sin(2x)) is -1/4 sin^3(x)cos(x)+3/8 x-3/8 sin(2x)

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expand-1/4 sin^3(x)cos(x)+3/8 (x-sin(2x))

expand

- \frac{1}{4} sin^{3} (x) cos (x) + \frac{3}{8} (x - sin (2 x))

- \frac{1}{4} sin^{3} (x) cos (x) + \frac{3}{8} x - \frac{3}{8} sin (2 x)

Solution steps

- \frac{1}{4} sin^{3} (x) cos (x) + \frac{3}{8} (x - sin (2 x))

Apply the distributive law:

a (b - c) = ab - a c

\frac{3}{8} (x - sin (2 x)) = \frac{3}{8} x - \frac{3}{8} sin (2 x)

= - \frac{1}{4} sin^{3} (x) cos (x) + \frac{3}{8} x - \frac{3}{8} sin (2 x)

\frac{k ( k + 2 )}{( k + 3 ) ^{2}}

\frac{d}{d x} ((z (x, y)) (10 x + 9 y)) - 11 x

\frac{x ( x ^{4} + x ^{3} + x ^{2} + x )}{x - 1}

(x^{\frac{1}{2}} + 1)^{2}

lo g_{10} (\frac{x - 1}{x ^{2} - 4})

What is expand-1/4 sin^3(x)cos(x)+3/8 (x-sin(2x)) ?
The solution to expand-1/4 sin^3(x)cos(x)+3/8 (x-sin(2x)) is -1/4 sin^3(x)cos(x)+3/8 x-3/8 sin(2x)