What is 8(z-1)((z-1)/2+1) ?

The solution to 8(z-1)((z-1)/2+1) is 4(z-1)(z+1)

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simplify 8(z-1)((z-1)/2+1)

simplify

8 (z - 1) (\frac{z - 1}{2} + 1)

4 (z - 1) (z + 1)

Solution steps

8 (z - 1) (\frac{z - 1}{2} + 1)

Join

\frac{z - 1}{2} + 1 : \frac{z + 1}{2}

= 8 (z - 1) \frac{z + 1}{2}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{8 ( z - 1 ) ( z + 1 )}{2}

Divide the numbers:

\frac{8}{2} = 4

= 4 (z - 1) (z + 1)

\frac{d}{d y} ((x) (e^{x} + x^{e}))

(1 + x)^{2} cos (x)

(i^{b + 6} - u p) (i^{b + 6} + u p)

(cos (θ) + sin (θ))^{5}

(cos (θ) + sin (θ))^{3}