What is expand (2+6sin(θ))^2 ?

The solution to expand (2+6sin(θ))^2 is 4+24sin(θ)+36sin^2(θ)

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expand (2+6sin(θ))^2

expand

(2 + 6 sin (θ))^{2}

4 + 24 sin (θ) + 36 sin^{2} (θ)

Solution steps

(2 + 6 sin (θ))^{2}

Apply Perfect Square Formula:

(a + b)^{2} = a^{2} + 2 ab + b^{2}

(2 + 6 sin (θ))^{2} = 2^{2} + 2 \cdot 2 \cdot 6 sin (θ) + (6 sin (θ))^{2}

= 2^{2} + 2 \cdot 2 \cdot 6 sin (θ) + (6 sin (θ))^{2}

Simplify

2^{2} + 2 \cdot 2 \cdot 6 sin (θ) + (6 sin (θ))^{2} : 4 + 24 sin (θ) + 36 sin^{2} (θ)

= 4 + 24 sin (θ) + 36 sin^{2} (θ)

(a x + b y) (c x - d y)

\frac{x + 1}{x ( x + 1 )} - \frac{( x - 1 ) x}{x ( x + 1 )}

\frac{x}{( ( 0.012 - x ) \cdot ( 0.04 - 4 x ) ^{4} )}

(a x + b y) (c + d y)

(a^{\frac{9}{2}} - b^{\frac{9}{2}})^{2}

What is expand (2+6sin(θ))^2 ?
The solution to expand (2+6sin(θ))^2 is 4+24sin(θ)+36sin^2(θ)