What is expand x^{1/3}(x^{2/3}-x) ?

The solution to expand x^{1/3}(x^{2/3}-x) is x-x^{4/3}

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expand x^{1/3}(x^{2/3}-x)

expand

x^{\frac{1}{3}} (x^{\frac{2}{3}} - x)

x - x^{\frac{4}{3}}

Solution steps

x^{\frac{1}{3}} (x^{\frac{2}{3}} - x)

Apply the distributive law:

a (b - c) = ab - a c

x^{\frac{1}{3}} (x^{\frac{2}{3}} - x) = x^{\frac{1}{3}} x^{\frac{2}{3}} - x^{\frac{1}{3}} x

= x^{\frac{1}{3}} x^{\frac{2}{3}} - x^{\frac{1}{3}} x

x^{\frac{1}{3}} x^{\frac{2}{3}} = x

x^{\frac{1}{3}} x = x^{\frac{4}{3}}

= x - x^{\frac{4}{3}}

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What is expand x^{1/3}(x^{2/3}-x) ?
The solution to expand x^{1/3}(x^{2/3}-x) is x-x^{4/3}