What is expand derivative of 2xe^x+(e^x)(x^2-5) ?

The solution to expand derivative of 2xe^x+(e^x)(x^2-5) is derivative of 2xe^x+e^xx^2-5e^x

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expand derivative of 2xe^x+(e^x)(x^2-5)

expand

\frac{d}{d x} (2 x e^{x}) + (e^{x}) (x^{2} - 5)

\frac{d}{d x} (2 x e^{x}) + e^{x} x^{2} - 5 e^{x}

Solution steps

\frac{d}{d x} (2 x e^{x}) + (e^{x}) (x^{2} - 5)

= \frac{d}{d x} (2 e^{x} x) + (e^{x}) (x^{2} - 5)

Expand

(e^{x}) (x^{2} - 5) : e^{x} x^{2} - 5 e^{x}

= \frac{d}{d x} (2 x e^{x}) + e^{x} x^{2} - 5 e^{x}

m (1 - cos (x))

2 (3 + 11)

(\frac{1}{x + 1} \circ 5 x + 2) (2)

- 4 (6 x^{3} - 3 x^{2} - 4)^{2}

(2 + 6 - x)^{2}

What is expand derivative of 2xe^x+(e^x)(x^2-5) ?
The solution to expand derivative of 2xe^x+(e^x)(x^2-5) is derivative of 2xe^x+e^xx^2-5e^x