What is expand (e^{2x})(3e^{3x}+2x) ?

The solution to expand (e^{2x})(3e^{3x}+2x) is 3e^{5x}+2e^{2x}x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (e^{2x})(3e^{3x}+2x)

expand

(e^{2 x}) (3 e^{3 x} + 2 x)

3 e^{5 x} + 2 e^{2 x} x

Solution steps

(e^{2 x}) (3 e^{3 x} + 2 x)

Apply the distributive law:

a (b + c) = ab + a c

a = (e^{2 x}), b = 3 e^{3 x}, c = 2 x

= (e^{2 x}) \cdot 3 e^{3 x} + (e^{2 x}) \cdot 2 x

= 3 e^{3 x} (e^{2 x}) + 2 x (e^{2 x})

Simplify

3 e^{3 x} (e^{2 x}) + 2 x (e^{2 x}) : 3 e^{5 x} + 2 e^{2 x} x

= 3 e^{5 x} + 2 e^{2 x} x

\frac{15}{( ( 5 k - 2 ) ( 5 k + 3 ) )}

\frac{3 ( x - 1 )}{( x + 1 )}

\frac{d}{d t} ((x) (3 x + y))

(x - 5 + 2 x + 4)^{2}

, (- 2, - 18) (- 18, 1)^{'}

What is expand (e^{2x})(3e^{3x}+2x) ?
The solution to expand (e^{2x})(3e^{3x}+2x) is 3e^{5x}+2e^{2x}x