What is expand (f/2 (l-x))((wx)/2 (l-x)) ?

The solution to expand (f/2 (l-x))((wx)/2 (l-x)) is (l^2fxw)/4-(lfx^2w)/2+(fx^3w)/4

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expand (f/2 (l-x))((wx)/2 (l-x))

expand

(\frac{f}{2} (l - x)) (\frac{w x}{2} (l - x))

\frac{l ^{2} f x w}{4} - \frac{l f x ^{2} w}{2} + \frac{f x ^{3} w}{4}

Solution steps

(\frac{f}{2} (l - x)) (\frac{w x}{2} (l - x))

Remove parentheses:

(a) = a

= \frac{f}{2} (l - x) \frac{w x}{2} (l - x)

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

(l - x) (l - x) = (l - x)^{1 + 1}

= \frac{f}{2} \cdot \frac{w x}{2} (l - x)^{1 + 1}

Add the numbers:

1 + 1 = 2

= \frac{f}{2} \cdot \frac{w x}{2} (l - x)^{2}

(l - x)^{2} = l^{2} - 2 l x + x^{2}

= \frac{x w}{2} \cdot \frac{f}{2} (x^{2} - 2 l x + l^{2})

Multiply fractions:

a \cdot \frac{b}{c} \cdot \frac{d}{e} = \frac{a \cdot b \cdot d}{c \cdot e}

= \frac{f w x ( l ^{2} - 2 l x + x ^{2} )}{2 \cdot 2}

Multiply the numbers:

2 \cdot 2 = 4

= \frac{f x w ( x ^{2} - 2 l x + l ^{2} )}{4}

Expand

f w x (l^{2} - 2 l x + x^{2}) : l^{2} f x w - 2 l f x^{2} w + f x^{3} w

= \frac{l ^{2} f x w - 2 l f x ^{2} w + f x ^{3} w}{4}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{l ^{2} f x w - 2 l f x ^{2} w + f x ^{3} w}{4} = \frac{l ^{2} f x w}{4} - \frac{2 l f x ^{2} w}{4} + \frac{f x ^{3} w}{4}

= \frac{l ^{2} f x w}{4} - \frac{2 l f x ^{2} w}{4} + \frac{f x ^{3} w}{4}

Cancel

\frac{2 l f x ^{2} w}{4} : \frac{l f x ^{2} w}{2}

= \frac{l ^{2} f x w}{4} - \frac{l f x ^{2} w}{2} + \frac{f x ^{3} w}{4}

3 (6 x + 9 y)^{2} (6 + 9 y^{'} (x))

(3 u^{2}, 3 u^{2}, 2 v) \times (3 v^{2}, - 3 v^{2}, 2 u)

(a^{2} + b^{2} + c^{2} + d^{2})^{2}

4 (a + e)

5 (6 + 7)

What is expand (f/2 (l-x))((wx)/2 (l-x)) ?
The solution to expand (f/2 (l-x))((wx)/2 (l-x)) is (l^2fxw)/4-(lfx^2w)/2+(fx^3w)/4