What is expand (x^{2n+2})/((n+1)!(2n+2)) ?

The solution to expand (x^{2n+2})/((n+1)!(2n+2)) is (x^{2n+2})/(2n(n+1)!+2(n+1)!)

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expand (x^{2n+2})/((n+1)!(2n+2))

expand

\frac{x ^{2 n + 2}}{( n + 1 ) ! ( 2 n + 2 )}

\frac{x ^{2 n + 2}}{2 n ( n + 1 ) ! + 2 ( n + 1 ) !}

Solution steps

\frac{x ^{2 n + 2}}{( n + 1 ) ! ( 2 n + 2 )}

Expand

(n + 1)! (2 n + 2) : 2 n (n + 1)! + 2 (n + 1)!

= \frac{x ^{2 n + 2}}{2 n ( n + 1 ) ! + 2 ( n + 1 ) !}

(3 + sin (t))^{2} + cos^{2} (t)

(6 - x - 3) (6 - x + 3)

\frac{2 ( x + 1 )}{25}

(x^{2} + 1) d y

\frac{2}{γ ( 2 - θ λ )}

What is expand (x^{2n+2})/((n+1)!(2n+2)) ?
The solution to expand (x^{2n+2})/((n+1)!(2n+2)) is (x^{2n+2})/(2n(n+1)!+2(n+1)!)