What is expand (x^2+x-1)^5 ?

The solution to expand (x^2+x-1)^5 is x^{10}+5x^9+5x^8-10x^7-15x^6+11x^5+15x^4-10x^3-5x^2+5x-1

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expand (x^2+x-1)^5

expand

(x^{2} + x - 1)^{5}

x^{10} + 5 x^{9} + 5 x^{8} - 10 x^{7} - 15 x^{6} + 11 x^{5} + 15 x^{4} - 10 x^{3} - 5 x^{2} + 5 x - 1

Solution steps

(x^{2} + x - 1)^{5}

(x^{2} + x - 1)^{5} = (x^{2} + x - 1) (x^{2} + x - 1) (x^{2} + x - 1) (x^{2} + x - 1) (x^{2} + x - 1)

= (x^{2} + x - 1) (x^{2} + x - 1) (x^{2} + x - 1) (x^{2} + x - 1) (x^{2} + x - 1)

Expand

(x^{2} + x - 1) (x^{2} + x - 1) (x^{2} + x - 1) (x^{2} + x - 1) (x^{2} + x - 1) : x^{10} + 5 x^{9} + 5 x^{8} - 10 x^{7} - 15 x^{6} + 11 x^{5} + 15 x^{4} - 10 x^{3} - 5 x^{2} + 5 x - 1

= x^{10} + 5 x^{9} + 5 x^{8} - 10 x^{7} - 15 x^{6} + 11 x^{5} + 15 x^{4} - 10 x^{3} - 5 x^{2} + 5 x - 1

(5 + 5 c) (20 - 15 c)

2 π (363 + 72)

\frac{18}{( 2 x + 3 ) x}

\frac{2}{( t ^{2} + 2 ) ^{2}}

\frac{7 ( 6 - 5 )}{31}

What is expand (x^2+x-1)^5 ?
The solution to expand (x^2+x-1)^5 is x^{10}+5x^9+5x^8-10x^7-15x^6+11x^5+15x^4-10x^3-5x^2+5x-1