What is expand P(1,-2)yQ(3,4) ?

The solution to expand P(1,-2)yQ(3,4) is 1*(3*4,)PyQ,-2(3*4,)PyQ

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expand P(1,-2)yQ(3,4)

expand

P (1, - 2) y Q (3, 4)

1 \cdot (3 \cdot 4,) P y Q, - 2 (3 \cdot 4,) P y Q

Solution steps

P (1, - 2) y Q (3, 4)

= (1, - 2) (3 \cdot 4,) P y Q

Apply the distributive law:

a (b - c) = ab - a c

a = P y Q (3, 4), b = 1,, c = 2

= P y Q (3, 4) \cdot 1, - P y Q (3, 4) \cdot 2

= 1 \cdot (3 \cdot 4,) P y Q, - 2 (3 \cdot 4,) P y Q

\frac{( 3 - 5 + x ) ( 2 + 8 - x )}{x - 4}

2 (a + 2 e)

\frac{x}{( x + 3 ) ( x - 2 )}

3 (3 + 6)

2 (2 y^{2} + 5 y^{3} - 4 y + 3)^{2}

What is expand P(1,-2)yQ(3,4) ?
The solution to expand P(1,-2)yQ(3,4) is 1*(3*4,)PyQ,-2(3*4,)PyQ