What is (2k^3+6k+1)-(2k^2+1) ?

The solution to (2k^3+6k+1)-(2k^2+1) is 2k^3-2k^2+6k

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simplify (2k^3+6k+1)-(2k^2+1)

simplify

(2 k^{3} + 6 k + 1) - (2 k^{2} + 1)

2 k^{3} - 2 k^{2} + 6 k

Solution steps

(2 k^{3} + 6 k + 1) - (2 k^{2} + 1)

Apply rule:

(a) = a

(2 k^{3} + 6 k + 1) = 2 k^{3} + 6 k + 1

= 2 k^{3} + 6 k + 1 - (2 k^{2} + 1)

Apply the distributive law:

- (a + b) = - a - b

- (2 k^{2} + 1) = - 2 k^{2} - 1

= 2 k^{3} + 6 k + 1 - 2 k^{2} - 1

Group like terms

= 2 k^{3} - 2 k^{2} + 6 k + 1 - 1

Subtract the numbers:

1 - 1 = 0

= 2 k^{3} - 2 k^{2} + 6 k

\frac{2 ( \frac{5}{7} - \frac{1}{2} )}{\frac{3}{5} - \frac{1}{3}}

3 x^{3} - 6 x^{5} + 9 x^{2}

18 x^{2} + 65 x + 7 = 0

\frac{8}{6} + (- \frac{9}{5})

5 x^{2} - 45

What is (2k^3+6k+1)-(2k^2+1) ?
The solution to (2k^3+6k+1)-(2k^2+1) is 2k^3-2k^2+6k