What is expand (f\circ g)(2x+1)-3 ?

The solution to expand (f\circ g)(2x+1)-3 is 2\circ fgx+\circ fg-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (f\circ g)(2x+1)-3

expand

(f \circ g) (2 x + 1) - 3

2 \circ f gx + \circ f g - 3

Solution steps

(f \circ g) (2 x + 1) - 3

= (\circ f g) (2 x + 1) - 3

Expand

(f \circ g) (2 x + 1) : 2 \circ f gx + \circ f g

= 2 \circ f gx + \circ f g - 3

d x d (x^{6} + 3 x^{4} + 7 x^{2})

\frac{s}{( s ^{2} + n ^{2} ) ( s - 4 )}

, \frac{3}{4} (v - 16)

(2 x - 3 y) (4 x - 5 y)

(22 - x)^{2}

What is expand (f\circ g)(2x+1)-3 ?
The solution to expand (f\circ g)(2x+1)-3 is 2\circ fgx+\circ fg-3