What is expand-3^{1/3}(2x^2-3x+5+2x^{1/2}-4x^{3/2}) ?

The solution to expand-3^{1/3}(2x^2-3x+5+2x^{1/2}-4x^{3/2}) is

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expand-3^{1/3}(2x^2-3x+5+2x^{1/2}-4x^{3/2})

expand

- 3^{\frac{1}{3}} (2 x^{2} - 3 x + 5 + 2 x^{\frac{1}{2}} - 4 x^{\frac{3}{2}})

- 3^{\frac{1}{3}} \cdot 2 x^{2} + 3^{\frac{1}{3}} \cdot 3 x - 3^{\frac{1}{3}} \cdot 5 - 3^{\frac{1}{3}} \cdot 2 x^{\frac{1}{2}} + 3^{\frac{1}{3}} \cdot 4 x^{\frac{3}{2}}

Solution steps

- 3^{\frac{1}{3}} (2 x^{2} - 3 x + 5 + 2 x^{\frac{1}{2}} - 4 x^{\frac{3}{2}})

Distribute parentheses

= - 3^{\frac{1}{3}} \cdot 2 x^{2} - 3^{\frac{1}{3}} (- 3 x) - 3^{\frac{1}{3}} \cdot 5 - 3^{\frac{1}{3}} \cdot 2 x^{\frac{1}{2}} - 3^{\frac{1}{3}} (- 4 x^{\frac{3}{2}})

Simplify

- 3^{\frac{1}{3}} \cdot 2 x^{2} - 3^{\frac{1}{3}} (- 3 x) - 3^{\frac{1}{3}} \cdot 5 - 3^{\frac{1}{3}} \cdot 2 x^{\frac{1}{2}} - 3^{\frac{1}{3}} (- 4 x^{\frac{3}{2}}) : - 3^{\frac{1}{3}} \cdot 2 x^{2} + 3^{\frac{1}{3}} \cdot 3 x - 3^{\frac{1}{3}} \cdot 5 - 3^{\frac{1}{3}} \cdot 2 x^{\frac{1}{2}} + 3^{\frac{1}{3}} \cdot 4 x^{\frac{3}{2}}

= - 3^{\frac{1}{3}} \cdot 2 x^{2} + 3^{\frac{1}{3}} \cdot 3 x - 3^{\frac{1}{3}} \cdot 5 - 3^{\frac{1}{3}} \cdot 2 x^{\frac{1}{2}} + 3^{\frac{1}{3}} \cdot 4 x^{\frac{3}{2}}

(1 + cos (x))^{2}

2 x^{2 x} (ln (x) + 1)

\frac{1}{s \cdot ( 1 + 2 \cdot s + 3 \cdot s ^{2} + 1.5 s ^{3} )}

y d x - 2 (x - y) d y

(6 cot (θ) + 5)^{2}

What is expand-3^{1/3}(2x^2-3x+5+2x^{1/2}-4x^{3/2}) ?
The solution to expand-3^{1/3}(2x^2-3x+5+2x^{1/2}-4x^{3/2}) is