What is expand (2cos(2x)cos(x)-cos(3x))sec(x) ?

The solution to expand (2cos(2x)cos(x)-cos(3x))sec(x) is 2sec(x)cos(2x)cos(x)-sec(x)cos(3x)

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expand (2cos(2x)cos(x)-cos(3x))sec(x)

expand

(2 cos (2 x) cos (x) - cos (3 x)) sec (x^{\circ})

2 sec (x^{\circ}) cos (2 x) cos (x) - sec (x^{\circ}) cos (3 x)

Solution steps

(2 cos (2 x) cos (x) - cos (3 x)) sec (x^{\circ})

= sec (x^{\circ}) (2 cos (2 x) cos (x) - cos (3 x))

Apply the distributive law:

a (b - c) = ab - a c

a = sec (x^{\circ}), b = 2 cos (2 x) cos (x), c = cos (3 x)

= sec (x^{\circ}) \cdot 2 cos (2 x) cos (x) - sec (x^{\circ}) cos (3 x)

= 2 sec (x^{\circ}) cos (2 x) cos (x) - sec (x^{\circ}) cos (3 x)

\frac{a}{12} \cdot \frac{9}{10}

- \frac{z ( 1 + x )}{( z + x y ) ^{2}}

(2 t + 2) (t - 32)

(1 - x) ((- 2 - x) (1 - x) - \frac{1}{4})

\frac{12}{x ( x ^{2} + 6 )}

What is expand (2cos(2x)cos(x)-cos(3x))sec(x) ?
The solution to expand (2cos(2x)cos(x)-cos(3x))sec(x) is 2sec(x)cos(2x)cos(x)-sec(x)cos(3x)