What is expand (1-sin(a)-cos(a))^2 ?

The solution to expand (1-sin(a)-cos(a))^2 is sin(2a)+2-2cos(a)-2sin(a)

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expand (1-sin(a)-cos(a))^2

expand

(1 - sin (a) - cos (a))^{2}

sin (2 a) + 2 - 2 cos (a) - 2 sin (a)

Solution steps

(1 - sin (a) - cos (a))^{2}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

(1 - sin (a) - cos (a))^{2} = (1 - sin (a) - cos (a)) (1 - sin (a) - cos (a))

= (1 - sin (a) - cos (a)) (1 - sin (a) - cos (a))

Distribute parentheses

= 1 \cdot 1 + 1 \cdot (- sin (a)) + 1 \cdot (- cos (a)) - sin (a) \cdot 1 - sin (a) (- sin (a)) - sin (a) (- cos (a)) - cos (a) \cdot 1 - cos (a) (- sin (a)) - cos (a) (- cos (a))

Simplify

1 \cdot 1 + 1 \cdot (- sin (a)) + 1 \cdot (- cos (a)) - sin (a) \cdot 1 - sin (a) (- sin (a)) - sin (a) (- cos (a)) - cos (a) \cdot 1 - cos (a) (- sin (a)) - cos (a) (- cos (a)) : sin (2 a) + 2 - 2 cos (a) - 2 sin (a)

= sin (2 a) + 2 - 2 cos (a) - 2 sin (a)

\frac{5 ( x ^{4} - 1 )}{2}

- \frac{a s}{( a ^{2} - s ^{2} ) ( s ^{2} - a ^{2} )}

\frac{d}{d v} ((p) (p + \frac{3.5}{v ^{2}}) (v - 2.1))

(- 8, - 1) (- 6, 5) y - 5

\frac{w ( L - x ) ^{3}}{3 L}

What is expand (1-sin(a)-cos(a))^2 ?
The solution to expand (1-sin(a)-cos(a))^2 is sin(2a)+2-2cos(a)-2sin(a)