What is expand (y+ln|e^y-2|)*ln(x) ?

The solution to expand (y+ln|e^y-2|)*ln(x) is yln(x)+ln|e^y-2|ln(x)

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expand (y+ln|e^y-2|)*ln(x)

expand

(y + ln ∣ e^{y} - 2 ∣) \cdot ln (x)

y ln (x) + ln ∣ e^{y} - 2 ∣ ln (x)

Solution steps

(y + ln ∣ e^{y} - 2 ∣) ln (x)

= ln (x) (y + ln ∣ e^{y} - 2 ∣)

Apply the distributive law:

a (b + c) = ab + a c

a = ln (x), b = y, c = ln ∣ e^{y} - 2 ∣

= ln (x) y + ln (x) ln ∣ e^{y} - 2 ∣

= y ln (x) + ln ∣ e^{y} - 2 ∣ ln (x)

\frac{( ( 8 + h ) ^{\frac{1}{3}} - 2 )}{h}

2 ((\frac{7}{4})^{\frac{1}{5}} - 1)

(9 x + 2) (5 x - 3)

(x - 9) (\frac{x}{36} + \frac{2}{27})

\frac{s}{( s - 1 ) ^{3}}

What is expand (y+ln|e^y-2|)*ln(x) ?
The solution to expand (y+ln|e^y-2|)*ln(x) is yln(x)+ln|e^y-2|ln(x)