What is expand (2x+y=1,6)(x+y=10) ?

The solution to expand (2x+y=1,6)(x+y=10) is 2x^2+2xy=10

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expand (2x+y=1,6)(x+y=10)

expand

(2 x + y = 1, 6) (x + y = 10)

2 x^{2} + 2 x y = 10

Solution steps

(2 x + y = 1, 6) (x + y = 10)

= (2 x + 1 \cdot 6 =, y) (x + 10 = y)

Apply FOIL method:

(a + b) (c + d) = a c + a d + b c + b d

a = 2 x, b = y = 1, 6, c = x, d = y = 10

2 xx + 2 x y = 10 + y = 1, 6 x + y = 1, 6 y = 10

Expand

2 xx + 2 x y : 2 x^{2} + 2 x y

2 x^{2} + 2 x y = 10

\frac{2 x ( x ^{2} - 3 ) ^{4}}{625}

x e^{3 x} (4 - 2 x) - 2

\frac{d ^{2}}{d x ^{2}} ((g (x, y)) (x^{2} y + cos (y) + y, x))

- \frac{133}{2} - \frac{43 ( 5 + 1 )}{8}

What is expand (2x+y=1,6)(x+y=10) ?
The solution to expand (2x+y=1,6)(x+y=10) is 2x^2+2xy=10