What is the answer to (x-3)(x+10)=x^2+13x-30 ?

The answer to (x-3)(x+10)=x^2+13x-30 is x=0

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(x-3)(x+10)=x^2+13x-30

(x - 3) (x + 10) = x^{2} + 13 x - 30

x = 0

Solution steps

(x - 3) (x + 10) = x^{2} + 13 x - 30

Expand

(x - 3) (x + 10) : x^{2} + 7 x - 30

x^{2} + 7 x - 30 = x^{2} + 13 x - 30

Move

30

to the right side

x^{2} + 7 x = x^{2} + 13 x

Subtract

x^{2} + 13 x

from both sides

x^{2} + 7 x - (x^{2} + 13 x) = x^{2} + 13 x - (x^{2} + 13 x)

Simplify

- 6 x = 0

Divide both sides by

- 6

x = 0

\frac{c}{2} \leq - 0.75

x + x + 82 = 352

z^{3} - 2 z^{2} + 9 z - 18

(\frac{81000}{0.059}) (1 - (\frac{1}{( 1.059 ) ^{30}}))

20 y^{7} + 10 y^{2}

What is the answer to (x-3)(x+10)=x^2+13x-30 ?
The answer to (x-3)(x+10)=x^2+13x-30 is x=0
Solve for x: (x-3)(x+10)=x^2+13x-30
The solution is x=0