What is expand-3(5-4csc(θ)=csc(θ)) ?

The solution to expand-3(5-4csc(θ)=csc(θ)) is -15+12csc(θ)=csc(θ)

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expand-3(5-4csc(θ)=csc(θ))

expand

- 3 (5 - 4 csc (θ) = csc (θ))

- 15 + 12 csc (θ) = csc (θ)

Solution steps

- 3 (5 - 4 csc (θ) = csc (θ))

= - 3 (5 - 4 = csc (θ) csc (θ))

Apply the distributive law:

a (b - c) = ab - a c

a = - 3, b = 5, c = 4 csc (θ) = csc (θ)

- 3 \cdot 5 - (- 3) \cdot 4 csc (θ) = csc (θ)

Apply minus-plus rules

- (- a) = a

- 3 \cdot 5 + 3 \cdot 4 csc (θ) = csc (θ)

Expand

- 3 \cdot 5 + 3 \cdot 4 csc (θ) : - 15 + 12 csc (θ)

- 15 + 12 csc (θ) = csc (θ)

v a l u e (g - f) (3)

lo g_{10} (10000 t)

\frac{( x - 1 ) ^{2} ( y - 3 )}{( 3 x - y ) ^{3}}

\frac{7 ( x + h ) ^{3} - 3}{( x + h ) ^{4}}

(e^{x}) (e^{x} x^{2} + 4 e^{x} x + 2 e^{x})

What is expand-3(5-4csc(θ)=csc(θ)) ?
The solution to expand-3(5-4csc(θ)=csc(θ)) is -15+12csc(θ)=csc(θ)