What is expand (1+ln(x))(-e+2x-xln(x)) ?

The solution to expand (1+ln(x))(-e+2x-xln(x)) is 2x+xln(x)-xln^2(x)-eln(x)-e

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expand (1+ln(x))(-e+2x-xln(x))

expand

(1 + ln (x)) (- e + 2 x - x ln (x))

2 x + x ln (x) - x ln^{2} (x) - e ln (x) - e

Solution steps

(1 + ln (x)) (- e + 2 x - x ln (x))

Distribute parentheses

= 1 \cdot (- e) + 1 \cdot 2 x + 1 \cdot (- x ln (x)) + ln (x) (- e) + ln (x) \cdot 2 x + ln (x) (- x ln (x))

Apply minus-plus rules

+ (- a) = - a

= - 1 e + 1 \cdot 2 x - 1 \cdot x ln (x) - e ln (x) + 2 x ln (x) - x ln (x) ln (x)

Simplify

- 1 e + 1 \cdot 2 x - 1 \cdot x ln (x) - e ln (x) + 2 x ln (x) - x ln (x) ln (x) : 2 x + x ln (x) - x ln^{2} (x) - e ln (x) - e

= 2 x + x ln (x) - x ln^{2} (x) - e ln (x) - e

(2 + 5) (2 + 5)

1 + x + y (- 1 - y^{'} (x))

(cos^{2} (v) + u (sin^{2} (v)))^{2}

\frac{( n + 2 )}{n ( n + 1 ) 2 ^{n + 1}}

(- 67 y + 97)^{2}

What is expand (1+ln(x))(-e+2x-xln(x)) ?
The solution to expand (1+ln(x))(-e+2x-xln(x)) is 2x+xln(x)-xln^2(x)-eln(x)-e