What is expand ((x-4)^2)/(x^2-9) ?

The solution to expand ((x-4)^2)/(x^2-9) is (x^2-8x+16)/(x^2-9)

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expand ((x-4)^2)/(x^2-9)

expand

\frac{( x - 4 ) ^{2}}{x ^{2} - 9}

\frac{x ^{2} - 8 x + 16}{x ^{2} - 9}

Solution steps

\frac{( x - 4 ) ^{2}}{x ^{2} - 9}

(x - 4)^{2} = x^{2} - 8 x + 16

= \frac{x ^{2} - 8 x + 16}{x ^{2} - 9}

(15 x^{4} - 3 x^{2} + 1) cos (x)

π (- \frac{x ^{5}}{5} + \frac{26 x ^{3}}{3} - 25 x) + C

\frac{10 ( a - b )}{a + b}

(1 - lo g_{2} (12)) \cdot (1 - lo g_{6} (12))

1.2 \cdot 1 0^{5}

What is expand ((x-4)^2)/(x^2-9) ?
The solution to expand ((x-4)^2)/(x^2-9) is (x^2-8x+16)/(x^2-9)